2[m-(4m+12)+8]=2(m+4)

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Solution for 2[m-(4m+12)+8]=2(m+4) equation:


Simplifying
2[m + -1(4m + 12) + 8] = 2(m + 4)

Reorder the terms:
2[m + -1(12 + 4m) + 8] = 2(m + 4)
2[m + (12 * -1 + 4m * -1) + 8] = 2(m + 4)
2[m + (-12 + -4m) + 8] = 2(m + 4)

Reorder the terms:
2[-12 + 8 + m + -4m] = 2(m + 4)

Combine like terms: -12 + 8 = -4
2[-4 + m + -4m] = 2(m + 4)

Combine like terms: m + -4m = -3m
2[-4 + -3m] = 2(m + 4)
[-4 * 2 + -3m * 2] = 2(m + 4)
[-8 + -6m] = 2(m + 4)

Reorder the terms:
-8 + -6m = 2(4 + m)
-8 + -6m = (4 * 2 + m * 2)
-8 + -6m = (8 + 2m)

Solving
-8 + -6m = 8 + 2m

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '-2m' to each side of the equation.
-8 + -6m + -2m = 8 + 2m + -2m

Combine like terms: -6m + -2m = -8m
-8 + -8m = 8 + 2m + -2m

Combine like terms: 2m + -2m = 0
-8 + -8m = 8 + 0
-8 + -8m = 8

Add '8' to each side of the equation.
-8 + 8 + -8m = 8 + 8

Combine like terms: -8 + 8 = 0
0 + -8m = 8 + 8
-8m = 8 + 8

Combine like terms: 8 + 8 = 16
-8m = 16

Divide each side by '-8'.
m = -2

Simplifying
m = -2

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